Video answer for \Delta_{\text {vap }} \mathrm{H}^{\Theta} for water is +40.79 \mathrm{kJ} \mathrm{mol}^{ 1} at 1 bar and 100^{\circ} \mathrm{C}. Change in internal energy for this vapourisation under A) b) ln((p2) (p1)) = ( Hvap) (R)((1) (T1) ( If \Delta {H}{vap }^{\circ} for {H}{2} {O} is 44 {kJ} {mol}^{ 1}, then amount of heat required to evaporate 9 {~g} of {H}_{2} {O} is : 18.5: Free Energy Chemistry LibreTexts Solved calculate the experimental deltaHvap. delta H vap R= Chegg.com
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